The radius of the base of a cylindrical oil is 4 metre find its hieght if it can contains 1408 kiloliters oil

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Solution

We know that 1 kl = 1m^3.
Therefore, 1408 kl = 1408 m^3
Volume of cylinder = pi r^2 h
Volume of cylindrical oil = 1408 m^3
1408= 22/7×(4)^2× height
1408= 22/7×16× height
1408×7/22=16×height
448=16×height
448/16=height
28m = height

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The radius of the base of a cylindrical oil is 4 metre find its hieght if it can contains 1408 kiloliters oil

We know that 1 kl = 1m^3. Therefore, 1408 kl = 1408 m^3 Volume of cylinder = pi r^2 h Volume of cylindrical oil = 1408 m^3 1408= 22/7×(4)^2× height 1408= 22/7×16× height 1408×7/22=16×height 448=16×height 448/16=height 28m = height

We know that 1 kl = 1m^3.
Therefore, 1408 kl = 1408 m^3
Volume of cylinder = pi r^2 h
Volume of cylindrical oil = 1408 m^3
1408= 22/7×(4)^2× height
1408= 22/7×16× height
1408×7/22=16×height
448=16×height
448/16=height
28m = height