The radius of the base of a cylindrical wooden block is 5 cm and its volume is 1100 cu cm. How many discs of radius 5 cm and height 2 cm can be cut from this block of wood?

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Solution

Radius of cylindrical disc (r) = 5 cm
Height of cylindrical disc (h) = 2 cm
Volume of cylindrical disc = πr²h
$= \frac{22}{7} \times 5 \times 5 \times 2 = 157 cu cm$
Number of discs that can be cut from the wooden block
= Volume of wooden block ÷ Volume of disc
= 1100 ÷ 157
= 7.006 = 7

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The radius of the base of a cylindrical wooden block is 5 cm and its volume is 1100 cu cm. How many discs of radius 5 cm and height 2 cm can be cut from this block of wood?

Radius of cylindrical disc (r) = 5 cm Height of cylindrical disc (h) = 2 cm Volume of cylindrical disc = πr2h =227×5×5×2=157 cu cm Number of discs that can be cut from the wooden block = Volume of wooden block ÷ Volume of disc = 1100 ÷ 157 = 7.006 = 7

Radius of cylindrical disc (r) = 5 cm
Height of cylindrical disc (h) = 2 cm
Volume of cylindrical disc = πr²h
$= \frac{22}{7} \times 5 \times 5 \times 2 = 157 cu cm$
Number of discs that can be cut from the wooden block
= Volume of wooden block ÷ Volume of disc
= 1100 ÷ 157
= 7.006 = 7