The radius of the base of conical tent is $5 c m$ . If the tent is $12 m$ high, find area of the convas required in making the tent.

Open in App

Solution

$\Rightarrow l^{2} = 12^{2} + 5^{2}$
$\Rightarrow l^{2} = 169 c m$
$\Rightarrow l = \sqrt{169} = 13$
$C . S . A = π r l = 65 π c m^{2}$

Suggest Corrections

Similar questions

Q. A conical tent is 12 m high and the radius of its base is 9 m. The cost of canvas required to make the tent at the rate of ₹14 per m², is __________.

Q. The radius of the base of a conical tent is

7 m

. The tent is

24 m

high. Find the cost of the canvas required to make the tent, if one square meter of canvas costs

R s . 180

Q. Note Use

π = \frac{22}{7}

, unless stated otherwise.
A conical tent is 10 m high and the radius of its base is 24 m. Find the slant height of the tent. If the cost of 1 m² canvas is ₹ 70, find the cost of canvas required to make the tent.

Q. The radius of a conical tent is

12 m

and the slant height is

5.6 m

. Find the length of canvas required to make the tent it the width of canvas is

4 m

A conical tent 10 m high and tha radius of its base is 24 m . Find the slant height of the rent. If the cost of $1 m^{2}$ canvas is Rs70, find the cost of canvas required to make the tent.

Join BYJU'S Learning Program

The radius of the base of conical tent is 5 cm. If the tent is 12 m high, find area of the convas required in making the tent.

⇒l2=122+52⇒l2=169 cm⇒l=√169=13C.S.A=πrl=65π cm2

The radius of the base of conical tent is $5 c m$ . If the tent is $12 m$ high, find area of the convas required in making the tent.

$\Rightarrow l^{2} = 12^{2} + 5^{2}$
$\Rightarrow l^{2} = 169 c m$
$\Rightarrow l = \sqrt{169} = 13$
$C . S . A = π r l = 65 π c m^{2}$