The radius of the circle given above is 7cm and the angle subtended by the arc is 60-If the area of -OAB is 21 cm2- then find the area of segment APBA- - 22-7

Area of sector OAPBO=60°/360°×π r^2 =60°/360°×22/7× 7^2=25.7 cm^2 Area of segment APBA Area of sector OAPBO Area of triangle OAB = 25.7 21 = 4.7 cm^2 Th ...

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Question

The radius of the circle given above is 7cm and the angle subtended by the arc is $60^{\circ}$ .
If the area of $Δ$ OAB is $21 {c m}^{2}$ , then find the area of segment APBA.
$(π = \frac{22}{7})$

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Solution

$Area of sector OAPBO = \frac{60 °}{360 °} \times π r^{2} = \frac{60 °}{360 °} \times \frac{22}{7} \times 7^{2} = 25.7 {c m}^{2}$

Area of segment APBA
Area of sector OAPBO - Area of triangle OAB
$= 25.7 - 21 = 4.7 {c m}^{2}$

Therefore, area of segment APBA
$= 4.7 {c m}^{2}$

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Similar questions

In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find:

(i) The length of the arc

(ii) Area of the sector formed by the arc

(iii) Area of the segment forced by the corresponding chord

Q. In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find (i) the length of the arc (ii) area of the sector formed by the arc. (Use π = 22/7)

The radius of the circle given above is 7cm and the angle subtended by the arc is $60^{\circ}$ . If the area of $Δ$ OAB is $21 {c m}^{2}$ , then the area of segment APB is___ .(Take the value of $π$ as $\frac{22}{7}$ )

The radius of the circle given above is 7cm and the angle subtended by the arc is $60^{\circ}$ .
If the area of $Δ$ OAB is $21 {c m}^{2}$ , then find the area of segment APBA.
$(π = \frac{22}{7})$

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The radius of the circle given above is 7cm and the angle subtended by the arc is 60∘. If the area of ΔOAB is 21cm2, then find the area of segment APBA. (π =227)

Area of sector OAPBO=60°360°×πr2=60°360°×227×72=25.7 cm2 Area of segment APBA Area of sector OAPBO - Area of triangle OAB =25.7−21=4.7 cm2 Therefore, area of segment APBA =4.7 cm2

The radius of the circle given above is 7cm and the angle subtended by the arc is $60^{\circ}$ .
If the area of $Δ$ OAB is $21 {c m}^{2}$ , then find the area of segment APBA.
$(π = \frac{22}{7})$

$Area of sector OAPBO = \frac{60 °}{360 °} \times π r^{2} = \frac{60 °}{360 °} \times \frac{22}{7} \times 7^{2} = 25.7 {c m}^{2}$

Area of segment APBA
Area of sector OAPBO - Area of triangle OAB
$= 25.7 - 21 = 4.7 {c m}^{2}$

Therefore, area of segment APBA
$= 4.7 {c m}^{2}$