The radius of the circle in which the sphere $x^{2} + y^{2} + z^{2} + 2 x - 2 y - 4 z - 19 = 0$ is cut by the plane x +2y +2z +7 =0 is

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Solution

The correct option is C 3
$p = \frac{- 1 + 2 + 4 + 7}{\sqrt{1 + 4 + 4}} = \frac{12}{3} = 4$

$∴ r = \sqrt{25 - 16} = 3$ .

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Similar questions

x^{2} + y^{2} + z^{2} + 2 x - 2 y - 4 z - 19 = 0

x + 2 y + 2 z + 7 = 0

x + 2 y + 2 z + 7 = 0

x^{2} + y^{2} + z^{2} + 2 x - 2 y - 4 z - 19 = 0

x^{2} + y^{2} + z^{2} + 2 x - 2 y - 4 z - 19 = 0 = x + 2 y + 2 z + 7

x + 2 y + 2 z = 15

x^{2} + y^{2} + z^{2} - 2 y - 4 z = 11

x^{2} + y^{2} = 4

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