wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The radius of the circle in which the sphere x2+y2+z2+2zāˆ’2yāˆ’4zāˆ’19=0 is cut by the plane x+2y+2z+7=0 is-

A
2
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
1
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is B 3
Centre and radius of the given sphere are (1,1,2) and 12+12+22+19=5 respectively
Now the perpendicular distance between centre of sphere to the given plane is given by,
d=∣ ∣1+2(1)+2(2)+712+22+22∣ ∣=4
Therefore radius of the circle in which the given sphere and plane cut is
=5242=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Sphere
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon