The radius of the circle passing through the foci of the ellipse x2-16-y2-9-1 and having its centre 0-3 is

The correct option is A 4a^2=16, b^2=9, e=7/4 ∴ Foci = (±√(7),0) Radius = distance from (0, 3) to (√(7),0)=4 ...

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Standard XII

Mathematics

Perpendicular Distance of a Point from a Line

The radius of...

Question

The radius of the circle passing through the foci of the ellipse $\frac{x^{2}}{16} + \frac{y^{2}}{9} = 1$ and having its centre (0, 3) is

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\sqrt{12}

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3.5

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Solution

The correct option is A 4
$a^{2} = 16, b^{2} = 9, e = \frac{7}{4}$
$∴ F o c i = (\pm \sqrt{7}, 0)$
Radius = distance from (0, 3) to $(\sqrt{7}, 0) = 4$

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The radius of the circle passing through the foci of the ellipse x216+y29=1 and having its centre (0, 3) is

The correct option is A 4a2=16,b2=9,e=74 ∴Foci=(±√7,0) Radius = distance from (0, 3) to (√7,0)=4

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The correct option is A 4
$a^{2} = 16, b^{2} = 9, e = \frac{7}{4}$
$∴ F o c i = (\pm \sqrt{7}, 0)$
Radius = distance from (0, 3) to $(\sqrt{7}, 0) = 4$