The radius of the circle passing through the points (1, 2), (5, 2) & (5, -2) is

2 \sqrt{2}

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2 \sqrt{5}

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3 \sqrt{2}

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5 \sqrt{2}

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Solution

The correct option is A $2 \sqrt{2}$
Centre of circle passing through (1,2), (5,2) and (5,-2) is mid point of C(1,2) and A (5,-2) .
We know,
Concept $\to$ diameter always from a right angle on a circle.
$∴ c e n t r e \equiv (\frac{1 + 5}{2}, \frac{2 - 2}{2})$
$\equiv (3, 0)$
and radius $= \frac{d i a m e t e r}{2} = \frac{\sqrt{(5 - 1)^{2} + (- 2 - 2)^{2}}}{2}$
$2 \sqrt{2}$

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The radius of the circle passing through the points (1, 2), (5, 2) & (5, -2) is

The correct option is A 2√2Centre of circle passing through (1,2), (5,2) and (5,-2) is mid point of C(1,2) and A (5,-2) .We know,Concept → diameter always from a right angle on a circle.∴centre≡(1+52,2−22)≡(3,0)and radius =diameter2=√(5−1)2+(−2−2)222√2