The radius of the circle x2 + y2 − 2x + 4y − 11 = 0
is
The radius of a circle x2 + y2 + 2gx + 2fy + c = 0
is √g2 + f2 − c.
Given, the equation is
x2 + y2 − 2x + 4y − 11 = 0
⇒ g = −1, f=2 and c=−11
⇒ r = √(−1)2 + (2)2 − (−11)
=√1+4+11
=√16=4 units