The radius of the circle, $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$ is .

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Solution

The correct option is D 4
The radius of the circle $x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ is $\sqrt{g^{2} + f^{2} - c}$

The equation of the circle given is $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$

$\Rightarrow g = - 1, f = 2$ and $c = 11$

$\Rightarrow$ Radius, $r = \sqrt{(- 1)^{2} + (2)^{2} - (- 11)}$

$= \sqrt{1 + 4 + 11}$

$= \sqrt{16} = 4$

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Find the radius of the circle $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$

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The radius of the circle S is same as the radius of $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$ and the centre of S is the centre of $x^{2} + y^{2} - 2 x - 4 y + 11 = 0$ . Find the equation of S.

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x^{2} + y^{2} + 2 x + 4 y - 11 = 0

externally and cuts the circle

x^{2} + y^{2} - 6 x + 8 y + k = 0

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The radius of the circle $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$
is .

Find the parametric equation of the circle $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$

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The radius of the circle, x2+y2−2x+4y−11=0 is .

The correct option is D 4The radius of the circle x2+y2+2gx+2fy+c=0 is √g2+f2−c The equation of the circle given is x2+y2−2x+4y−11=0 ⇒g=−1, f=2 and c=11 ⇒ Radius, r=√(−1)2+(2)2−(−11) =√1+4+11 =√16=4

The radius of the circle, $x^{2} + y^{2} - 2 x + 4 y - 11 = 0$ is .