The radius of the circle $x^{2} + y^{2} + 4 x + 6 y + 13 = 0$ is

\sqrt{26}

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\sqrt{13}

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\sqrt{23}

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Solution

Given equation of circle is $x^{2} + y^{2} + 4 x + 6 y + 13 = 0$
Radius = $\sqrt{g^{2} + f^{2} - c} = \sqrt{4 + 9 - 13} = 0.$

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2^{nd}

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