The radius of the hydrogen atom in the ground state is $0.53 A^{0}$ . The radius of $_{3} {L i}^{2 +}$ ion in the similar state is:

1.06 A^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.265 A^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.17 A^{0}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.53 A^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.17 A^{0}$
$r a d i u s \propto \frac{n^{2}}{Z}$
atomic number of $L i^{2 +} \Rightarrow Z = 3$
$r a d i u s = \frac{0.53 A^{o}}{3} = 0.176 A^{0}$

Suggest Corrections

Similar questions

0 A

L i^{2 +}

6)The radius of hydrogen atom in the ground state is 0.53Å. The radius of ₃Li²⁺ in the similar state is

˚ A

L i^{2 +}

a_{0}

ψ = \frac{1}{4 \sqrt{2 π}} (\frac{1}{a_{0}})^{\frac{3}{2}} (2 - \frac{r_{0}}{a_{0}}) e^{-} \frac{r_{0}}{a_{0}}

a_{0}

2 s

r_{0}

r_{0}

a_{0}

x a_{0} = r_{0}

x

Join BYJU'S Learning Program