Question

The radius of the nucleus of an atom of mass number $216$ is ($R_0=$ 1.2 fermi) :

• A. $7.2\times 10$${}^{-15}$m
• B. $7.2\times 10$${}^{-15}$fermi
• C. $14.4\times 10$${}^{-15}$m
• D. $1.44\times 10$${}^{-15}$mferm

Answer 1

Answer: (A)

$7.2\times 10$${}^{-15}$m

$R=R_0{A}^{\frac{1}{3}}$
$R=1.2\times {10}^{-15}\times (216{)}^{\frac{1}{3}}$
$=7.2\times {10}^{-15}m$