Question

The radius of the nucleus whose mass number is $216$ is [Take $R_0=1.3\text{fm}$]

• A. $9.8\text{fm}$
• B. $8.8\text{fm}$
• C. $7.8\text{fm}$
• D. $6.8fm$

Answer 1

The correct option is C $7.8\text{fm}$

Given:
$A=216$
$R_0=1.3\text{fm}=1.3\times {10}^{-15}\text{m}$

We know that, the expression for nuclear radius is given by

$R=R_0{A}^{\frac{1}{3}}$

$\Rightarrow R=1.3\times {10}^{-15}\times (216{)}^{\frac{1}{3}}$

$\Rightarrow R=1.3\times 6\times {10}^{-15}$

$\Rightarrow R=7.8\times {10}^{-15}\text{m}$

$\Rightarrow R=7.8\text{fm}$

Hence, option $\left(C\right)$ is correct.