Question

The radius of the orbital of electron in the hydrogen atom 0.5 $A^{\circ }$. The speed of the electron is. $2\times {10}^6\frac{m}{s}$. Then the current in the loop due to the motion of the electron is

• A. 1 mA
• B. 1.5 mA
• C. 2.5 mA
• D. 1.5 ×10^-2 mA

Answer 1

The correct option is A

1 mA

Time period of revolution of electron $T=\frac{2\pi }{\omega }=\frac{2\pi r}{v}$

Hence corresponding electric current $i=\frac{e}{T}=\frac{ev}{2\pi r}\Rightarrow \frac{1.6\times {10}^{-19}\times 2\times {10}^6}{2\times 3.14\times 0.5\times {10}^{-10}}=1mA.\}$