The radius of the second Bohr orbit for hydrogen atom is-Planck-s constant h -6-6262 - 10-34 J s- mass of an electron -9-1091 - 10-31 kg- charge of an electron e -1-60210 - 10-19 C- permittivity of vacuum -8-854185 - 10-12 kg -1 m -3 A 2A- 4-76 AB- 0-529 AC- 2-12 AD- 1-65 A

The correct option is C 2.12 ∘Ar_n=0.53n^2/Z∘A n=2 Z=1 r_2=0.53 × 4∘A=2.12 ∘A ...

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The De Broglie Explanation

The radius of...

Question

The radius of the second Bohr orbit for hydrogen atom is:
(Planck’s constant $h = 6.6262 \times 10^{- 34} J s$ ; mass of an electron $= 9.1091 \times 10^{- 31} k g$ ; charge of an electron
$e = 1.60210 \times 10^{- 19} C$ ; permittivity of vacuum $ϵ_{ϕ} = 8.854185 \times 10^{- 12} k g^{- 1} m^{- 3} A^{2})$

4.76 \circ A

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0.529 \circ A

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2.12 \circ A

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1.65 \circ A

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h = 6.6262 \times 10^{- 34} J s

= 9.1091 \times 10^{- 31} k g

e = 1.60210 \times 10^{- 19} C

ε_{0} = 8.854185 \times 10^{- 12} k g^{- 1} m^{- 3} A^{2}

h = 6.6262 \times 10^{- 34}

m = 9.1091 \times 10^{- 31}

e = 1.60210 \times 10^{- 19}

ϵ_{0} = 8.854185 \times 10^{- 12} C^{2} N^{- 1} m^{- 2}

(Planck's constant, h = 6.262 \times 10^{- 34} Js :

Mass of electron = 9.1091 \times 10^{- 31} kg;

Charge of electron, e = 1.60210 \times 10^{- 19} C;

permittivity of vacuum, ε_{0} = 8.854185 \times 10^{- 12} {kg}^{- 1} m^{- 3} A^{2})

9.1 \times 10^{- 31} K g

= 1.6 \times 10^{- 19} C

6.63 \times 10^{- 34} J - s

8.85 \times 10^{- 12} C^{2} / N m^{2}

(| e | = 1.6 \times 10^{- 19} C, m_{e} = 9.1 \times 10^{- 31} k g, h = 6.6 \times 10^{- 34} J s) .

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