The radius of the sphere $x^{2} + y^{2} + z^{2} - 2 x + 4 y - 6 z + 7 = 0$ is

49

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5

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- 7

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\sqrt{7}

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Solution

The correct option is D $\sqrt{7}$
Given equation of the sphere is,
$x^{2} + y^{2} + z^{2} - 2 x + 4 y - 6 z + 7 = 0$
$\Rightarrow (x - 1)^{2} + (y + 2)^{2} + (z - 3)^{2} = 7 = (\sqrt{7})^{2}$
Hence, radius of the sphere is $\sqrt{7}$ .

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