Question

The radius of two circles are 8 cm and 6 cm respectively. The radius of the circle having area equal to the sum of the areas of the two circles is

Answer 1

Sum of areas of two circles=$\pi (r_1^2+r_2^2)$

=$\pi (8^2+6^2)=100\pi$

Area\quad of\quad the\quad new\quad circle=Sum of areas of two circles=$100\pi$

$\pi R^2=100\pi R=10cm$