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Question

The random variable X has a probability distribution P(X) of the following form, where 'k' is some number.
P(X)=⎪ ⎪⎪ ⎪k, if x = 02k, if x = 13k, if x = 20, otherwise

Determine the value of k.

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Solution

Since, X has a probability distribution
P(X)=1
According to the values given in the question,
P(X) = P(X=0)+P(X=1)+P(X=2)+P(X>2)1 = k+2k+3k+06k = 1k = 16

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