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Question

The random variable X has probability distribution P(X) of the following form, where k is some number:

(a) Determine the value of k.

(b) Find P(X < 2), P(X ≥ 2), P(X ≥ 2).

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Solution

(a) It is known that the sum of probabilities of a probability distribution of random variables is one.

k + 2k + 3k + 0 = 1

⇒ 6k = 1

k =

(b) P(X < 2) = P(X = 0) + P(X = 1)


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