The range of a for which f(x)=sgn((sinx)+a) is continuous for all x∈R.
A
[−1,1]
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B
(−∞,−1)∪(1,∞)
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C
(−1,1)
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D
(−∞,−1]∪[1,∞)
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Solution
The correct option is B(−∞,−1)∪(1,∞) For f(x)=sgn((sinx)+a) to be continuous ((sinx)+a) must be either always positive or always negative.
For being always positive : −1+a>0⇒a>1
For being always negative : 1+a<0⇒a<−1 ⇒a∈(−∞,−1)∪(1,∞)