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Question

The range of a for which x2ax+12a2 is always positive for all real values of x, is 


A
(23,23)
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B
[23,23]
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C
(,1)
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D
(23,23]
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Solution

The correct option is C (23,23)
x2ax+12a2>0,   xR
So, 
D<0(a)24(12a2)<09a24<0a2<49a(23,23)

Mathematics

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