Question

The range of a particle when launched at an angle of ${15}^{\circ }$ with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of ${45}^{\circ }$ to the horizontal

• A. 1.5 km
• B. 3.0 km
• C. 6.0 km
• D. 0.75 km

Answer 1

The correct option is B 3.0 km

$R_{{15}^{\circ }}=\frac{u^{2}sin(2\times {15}^{\circ })}{g}=\frac{u^2}{2g}=1.5km$
$R_{{45}^{\circ }}=\frac{u^{2}sin(2\times {45}^{\circ })}{g}=\frac{u^2}{g}=1.5\times 2=3km$