Question

The range of a particle when launched at an angle of ${15}^{\circ }$ with the horizontal is $1.5km$. What is the range of the projectile when launched at an angle of ${45}^{\circ }$ to the horizontal?

• A. $1.5km$
• B. $3.0km$
• C. $6.0\text{km}$
• D. $0.75\text{km}$

Answer 1

The correct option is B $3.0km$

We know that,
$R=\frac{u^2\sin \left(2\theta \right)}{g}$
Putting the values,
$R_{{15}^{\circ }}=\frac{u^2\sin (2\times {15}^{\circ })}{g}=\frac{u^2}{2g}=1.5km$
$R_{{45}^{\circ }}=\frac{u^2\sin (2\times {45}^{\circ })}{g}=\frac{u^2}{g}=1.5\times 2=3km$