Question

The range of a projectile for a given initial velocity is maximum when the angle of projection is $45$.The range will be minimum, if the angle of projection is:

• A. 90
• B. 180
• C. 60
• D. 75

Answer 1

The correct option is A 90

$R=\frac{u^2\sin 2\theta }{g}$

Minimum value of range can be zero.

$\therefore R=0$ at $2\theta =0$

or $2\theta =180°$

So, $\theta =0$ or $\theta =90°$