Question

The range of a projectile, which is launched at an angle of ${15}^o$ with the horizontal, is $150m$. What is the range for an angle of projection of ${45}^o$ to the horizontal?

• A. $300m$
• B. $500m$
• C. $120m$
• D. $720m$

Answer 1

The correct option is A $300m$

$R=\frac{u^2\sin 2\theta }{g}$
From first condition,
$150=\frac{u^2\sin {30}^o}{g}$
$\Rightarrow \frac{u^2}{g}=300$
For $\theta ={45}^o$ range of projectile is
$R=\frac{u^2\sin {90}^o}{g}$
$R=\frac{u^2}{g}=300m$