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B
(1,∞)
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C
[−√2,−1]∪[1,√2]
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D
(−∞,−1)∪(1,∞)
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Solution
The correct option is A[1,√2] Given f(x)=sec(π4cos2x)
We know that, 0≤cos2x≤1 ⇒0≤π4cos2x≤π4
By graph of y=secx
Clearly, for y=secx when x∈[0,π4],secx∈[1,√2] ∴ range ∈[1,√2]