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Question

The range of f(x)=sin2x2sinx is

A
[1,3]
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B
[1,3)
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C
[0,3]
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D
(0,3)
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Solution

The correct option is A [1,3]
We have,
f(x)=sin2x2sinxf(x)=sin2x2sinx+11f(x)=(sinx1)21

We know that
1sinx12sinx100(sinx1)241(sinx1)213
Thus f(x)[1,3]

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