Question

The range of f(x) = |x – 2| + |x – 12| is

• A. $[2,\infty )$
• B. $[12,\infty )$
• C. $[10,\infty )$
• D. $[14,\infty )$

Answer 1

The correct option is C $[10,\infty )$

$f\left(x\right)=|x-2|+|x-12|$
Minimum value occurs at $x=\frac{2+12}{2}=7$
$\therefore range=[10,\infty )$