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Question

The range of log3[2(sinxcosx)+3] is

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Solution

log3[2(sinxcosx)+3]

a2+b2asinx+bcosxa2+b2

2(sinxcosx)222(sinxcosx)21{3(sinxcosx)+3}5

log31log3{2(sinxcosx)+3}log35

0f(x)2log35

Range[0,2log35]

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