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Question

The range of m for which the equation (log2x)24log2xm22m13=0 has real roots is

A
(,0)
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B
(0,)
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C
[1,)
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D
(,)
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Solution

The correct option is D (,)
(log2x)24log2xm22m13=0
Let log2x=tx=2t,tR
t24t(m2+2m+13)=0(1)
For the given equation to have real roots, equation (1) should have real roots. So,
D016+4(m2+2m+13)0m2+2m+170(m+1)2+160mR

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