The range of m for which the equation (log2x)2â4log2xâm2â2mâ13=0 has real roots is
A
(−∞,0)
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B
(0,∞)
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C
[1,∞)
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D
(−∞,∞)
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Solution
The correct option is D(−∞,∞) (log2x)2−4log2x−m2−2m−13=0
Let log2x=t⇒x=2t,t∈R t2−4t−(m2+2m+13)=0⋯(1)
For the given equation to have real roots, equation (1) should have real roots. So, D≥0⇒16+4(m2+2m+13)≥0⇒m2+2m+17≥0⇒(m+1)2+16≥0⇒m∈R