The range of fx-x-x is

The correct option is C [0,∞) For f to be defined term inside square root has to #160;be greater than zero. ⇒ |x| x≥ 0 |x|≥ x. ...

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Standard XII

Mathematics

Definition of Functions

The range of ...

Question

The range of $f (x) = \sqrt{| x | - x}$ is

(- \infty, \infty)

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(0, 1)

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[0, \infty)

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(0, 2)

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Solution

The correct option is C $[0, \infty)$
For $f$ to be defined term inside square root has to be greater than zero.
$\Rightarrow | x | - x \geq 0$
$| x | \geq x .$

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The range of f(x)=√|x|−x is

The correct option is C [0,∞)For f to be defined term inside square root has to be greater than zero.⇒|x|−x≥0|x|≥x.

The range of $f (x) = \sqrt{| x | - x}$ is

The correct option is C $[0, \infty)$
For $f$ to be defined term inside square root has to be greater than zero.
$\Rightarrow | x | - x \geq 0$
$| x | \geq x .$