The range of -1 x isA- -2- -2-B- -2- -2- -0- -2D- -0- -

The correct option is C [0,π] {π/2}The principle domain of the function x is the range of its inverse function. The range of ^ 1x= the principle domain of x= ...

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Standard VI

Mathematics

Idea of a Set

The range of ...

Question

The range of ${sec}^{- 1} x$ is

[- \frac{π}{2}, \frac{π}{2}]

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(- \frac{π}{2}, \frac{π}{2})

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[0, π]

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[0, π] - {\frac{π}{2}}

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Solution

The correct option is D $[0, π] - {\frac{π}{2}}$
The principle domain of the function $sec x$ is the range of its inverse function.
The range of ${sec}^{- 1} x$ = the principle domain of $sec x$ = $[0, π] - {\frac{π}{2}}$

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The range of sec−1x is

The correct option is D [0,π]−{π2}The principle domain of the function secx is the range of its inverse function. The range of sec−1x= the principle domain of secx= [0,π]−{π2}

The range of ${sec}^{- 1} x$ is

The correct option is D $[0, π] - {\frac{π}{2}}$
The principle domain of the function $sec x$ is the range of its inverse function.
The range of ${sec}^{- 1} x$ = the principle domain of $sec x$ = $[0, π] - {\frac{π}{2}}$