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Question

The range of sin1xcos1x is

A
[3π2,π2]
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B
[5π2,π3]
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C
[3π2,π]
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D
[0,π2]
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Solution

The correct option is A [3π2,π2]
sin1cos1x=π2cos1xcos1x=π22cos1x
0cos1xπ02cos1x2π2π2cos1x03π2π22cos1xπ2
Range =[3π2,π2]

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