The range of the expression f(x)=3x2−12x+5 is
Compare 3x2−12x+5 with ax2−bx+c
Here, a > 0 ⇒ Minimum value of f(x) occur at x=−b2a and the value is −D4a
D=b2−4ac
=(12)2−4(3)(5)
Minimum value = −8412=−7
As a > 0, graph of f(x) is upward.
As minimum value is -7,
Maximum value extends to ∞
So, the range is [-7, ∞)