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B
(2,∞)
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C
[2,6)∪(6,∞)
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D
(−1,∞)
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Solution
The correct option is A[2,∞) f(x)=x3+x2+x−3x−1 x3+x2+x−3=(x−1)(x2+2x+3) ⇒f(x)=x2+2x+3,x≠1
The graph of y=f(x) is shown in figure, that shows f(1) is included from left branch corresponding to f(−3). fmin occurs at x=−22=−1 fmin=2 Hence, its range is [2,∞)