The range of the function f(x)=|2x+1|−2|x−1|,xϵR, is
A
[−3,3]
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B
[0,6]
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C
R
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D
none of these
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Solution
The correct option is A[−3,3] f(x)=∣2x+1∣−2∣x−1∣ Now if −∞<x≤−1/2 f(x)=−(2x+1)+2(x−1)=−3 if −1/2<x≤1 f(x)=(2x+1)+2(x−1)=4x−1 if 1<x≤∞ f(x)=(2x+1)−2(x−1)=3 Hence Range of f(x) is [−3,3]