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Question

The range of the function f(x)=|2x+1|2|x1|, xϵR, is

A
[3,3]
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B
[0,6]
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C
R
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D
none of these
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Solution

The correct option is A [3,3]
f(x)=2x+12x1
Now if <x1/2
f(x)=(2x+1)+2(x1)=3
if 1/2<x1
f(x)=(2x+1)+2(x1)=4x1
if 1<x
f(x)=(2x+1)2(x1)=3
Hence Range of f(x) is [3,3]

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