CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The range of the function f(x)=3sinx2cosx is -

A
[13,13]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
[2,3]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[3,13]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[0,13]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A [13,13]
Then f(x)=3sinx2cosx.
Let, 3=rcosa,2=rsina, where r=13 and a=tan123.
Then f(x)=rsin(xa).
As 1sin(xa)1
rrsin(xa)r
or, 13rsin(xa)13.
13rsin(xa)13.
So, the range of the function f(x) is [13,13].

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon