The range of the function f x -3 sin x -5 cos x -1 isA- -2- -2-B- -3-8- -1-34- 1-34-D- R

The correct option is C [1 √(34), 1 + √(34)]f(x)=3 sin x 5 cos x + 1 Range of a sin x + b cos x + c is [c √(a^2+b^2), c+√(a^2 +b^2)] i.e. [1 √(9+25),1+√(9+ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Onto Function

The range of ...

Question

The range of the function f(x) = 3sin x – 5cos x + 1 is

[- \sqrt{2}, \sqrt{2}]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[3, 8]

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[1 - \sqrt{34}, 1 + \sqrt{34}]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $[1 - \sqrt{34}, 1 + \sqrt{34}]$
$f (x) = 3 s i n x - 5 c o s x + 1$
Range of $a s i n x + b c o s x + c i s [c - \sqrt{a^{2} + b^{2}}, c + \sqrt{a^{2} + b^{2}}]$
i.e. $[1 - \sqrt{9 + 25}, 1 + \sqrt{9 + 25}]$

Suggest Corrections

Similar questions

Q. The range of the function

f (x) = \frac{1}{3 sin x + 4 cos x - 2}

Q. The range of the function

f (x) = 2 | x - 1 | + | x + 2 |

- 1 \leq x \leq 2

Q. The range of the function

f (x) = \frac{2 + x}{2 - x}, x \neq 2

Q. The range of

f (x) = \frac{x + 2}{x - 3}

$R a n g e o f t h e f u n c t i o n f (x) = x^{2} + \frac{1}{x^{2} + 1}, i s$

Join BYJU'S Learning Program

The range of the function f(x) = 3sin x – 5cos x + 1 is

The correct option is C [1−√34,1+√34]f(x)=3 sin x−5 cos x+1 Range of a sin x+b cos x+c is [c−√a2+b2,c+√a2+b2] i.e. [1−√9+25,1+√9+25]

The correct option is C $[1 - \sqrt{34}, 1 + \sqrt{34}]$
$f (x) = 3 s i n x - 5 c o s x + 1$
Range of $a s i n x + b c o s x + c i s [c - \sqrt{a^{2} + b^{2}}, c + \sqrt{a^{2} + b^{2}}]$
i.e. $[1 - \sqrt{9 + 25}, 1 + \sqrt{9 + 25}]$