The range of the function f x -7- x P x -3 isA- 1-2-3-4-5B- 1-2-3C- 1-2-3-4D- 1-2-3-4-5-6

The correct option is B 1,2,3f(x) is defined ⇒ x 3 ≥ 0, x 3 ≤ 7 x ⇒ x ≥ 3 , 2x ≤ 10 ⇒ 3 ≤ x ≤ 5 ⇒ x=3 or 4 or 5 Range = { f(3),f(4),f(5) }={ ^4 P _0,^3 P _1 ...

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Byju's Answer

Standard XII

Mathematics

Global Minima

The range of ...

Question

$T h e r a n g e o f t h e f u n c t i o n f (x) =^{7 - x} P_{x - 3} i s$

{1,2,3}

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{1,2,3,4,5}

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{1,2,3,4}

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{1,2,3,4,5,6}

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Solution

The correct option is A {1,2,3}
$f (x) i s d e f i n e d \Rightarrow x - 3 \geq 0, x - 3 \leq 7 - x \Rightarrow x \geq 3, 2 x \leq 10 \Rightarrow 3 \leq x \leq 5 \Rightarrow x = 3 o r 4 o r 5 R a n g e = {f (3), f (4), f (5)} = {^{4} P_{0},^{3} P_{1},^{2} P_{2}} = {1, 3, 2}$

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Similar questions

Q. The range of the function

f (x) =^{7 - x} P_{x - 3}

is:

Q. The range of the function

f (x) =^{7 - x} P_{x - 3}

Q. If

f (x) =^{7 - x} P_{x - 3}

find domain and range of

f (x)

Q. The domain of the function defined by

f (x) =^{(7 - x)} P_{(x - 3)}

For the relation R= {(1,2),(2,3),(4,5),(3,6)}

The domain is

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The range of the function f(x)=7−xPx−3 is

The correct option is A {1,2,3}f(x) is defined ⇒ x−3≥0,x−3≤7−x⇒x≥3,2x≤10⇒3≤x≤5⇒x=3 or 4 or 5Range={f(3),f(4),f(5)}={4P0,3P1,2P2}={1,3,2}

$T h e r a n g e o f t h e f u n c t i o n f (x) =^{7 - x} P_{x - 3} i s$

The correct option is A {1,2,3}
$f (x) i s d e f i n e d \Rightarrow x - 3 \geq 0, x - 3 \leq 7 - x \Rightarrow x \geq 3, 2 x \leq 10 \Rightarrow 3 \leq x \leq 5 \Rightarrow x = 3 o r 4 o r 5 R a n g e = {f (3), f (4), f (5)} = {^{4} P_{0},^{3} P_{1},^{2} P_{2}} = {1, 3, 2}$