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Question

The range of the function f(x)=exInx5(x2+2)(x27x+10)2x211x+12 is

A
(,)
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B
[0,)
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C
(32,)
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D
(32,4)
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Solution

The correct option is A (,)
f(x)=exlnx(x2+2)(x25x2x+10)2x28x3x+12
=exlnx(x2+2)(x2)(x5)(2x3)(x4)
domain=R{32,4}.
But f(x) in defend for all value of x as per the group of f(x).
Hence Range of f(x)=(,).

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