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B
(−∞,0)
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C
(−∞,∞)
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D
None
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Solution
The correct option is C(−∞,∞) Given, f(x)=ex−e−x ∴f′(x)=ex+e−x>0∀x∈R Thus f(x) is strictly increasing function and it is continuous as well, Now f(−∞)=−∞ and f(∞)=∞ Hence range of f(x) is (−∞,∞)