MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Basic Inverse Trigonometric Functions

The Range of ...

Question

The Range of The function $f (x) = {sec}^{- 1} x$ is .

A

(0, π)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

(0, π] - (\frac{π}{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

(\frac{- π}{2}, \frac{π}{2}] - (0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

(\frac{- π}{2}, \frac{π}{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(0, π] - (\frac{π}{2}}$
The Range of ${sec}^{- 1}$
is $(0, π] - (\frac{π}{2}} .$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The range of the function

f (x) = (s i n^{- 1} x + t a n^{- 1} x + s e c^{- 1} x)

Q. The range of the function,

f (x) = {cot}^{- 1} x + {sec}^{- 1} x + {cosec}^{- 1} x

Q. Range of the function

f (x) = 4 {tan}^{- 1} x + 3 {sin}^{- 1} x + {sec}^{- 1} x

Q. The range of the the function,

f (x) = ({cot}^{- 1} x + {sec}^{- 1} x + c o s e c^{- 1} x)

Q. The range of the function

f (x) = {sec}^{- 1} (x) + {tan}^{- 1} (x)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Basic Inverse Trigonometric Functions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Basic Inverse Trigonometric Functions

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon