CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The range of the function f(x)=|x1|+|x2|+|x+1|+|x+2| where, x ϵ[2,2] is

A
[6,8]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
[2,4]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[0,4]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
{1,2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A [6,8]
f(x)=|x1|+|x2|+|x+1|+|x+2|
when x ϵ[2,1]
f(x)=(x1)(x2)(x+1)+(x+2)=2x+4
when x ϵ[1,1], f(x)=(x1)(x2)+x+1+x+2
=x+1x+2+x+1+x+2=6
when x ϵ[1,2], f(x)=(x1)(x2)+x+1+x+2=2x+4
Plotting the graph of the function, range of f(x)=[6,8]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Finding the Range of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon