wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The range of the function f(x)=|x2+2x15| is

A
R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
R+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
R{0}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[0,)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D [0,)
Clearly, domain of f is R.
x2+2x15=(x+1)216
16x2+2x15<
0|x2+2x15|<

Hence, range of f is [0,)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon