wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The range of the the function, f(x)=(cot1x+sec1x+cosec1x) is

A
(π2,3π2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(π2,3π4][5π4,3π2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
[π2,π)(π,3π2]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(π2,π)(π,3π2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (π2,3π4][5π4,3π2)
Given,
f(x)=(cot1x+sec1x+cosec1x)

Now,
0<cot1x<π ..(1)
0sec1x<π2
and
π2<sec1xπ ...(2)

π2cosec1x<0 and 0<cosec1π2 ..(3)

Adding (1) , (2) and (3), we get
π2<cot1x+sec1x+cosec1x3π4 and 5π4cot1x+sec1x+cosec1x<3π2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Inverse Trigonometric Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon