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Question

The rank of a 3 × 3 matrix C (= AB), found by multiplying a non-zero column matrix A of size 3 × 1 and a non-zero row matrix B of size 1 × 3, is

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is B 1
Let A = a1b1c1 & B = [a2b2c2]

rank of A = r(A) = 1
rank of B = r(B) = 1

Rank of (AB) minimum (Rank (A), Rank (B))

r(AB) 1

So, rank (AB) is either 0 or 1

ButAB0

Rank(AB)=1

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