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Question

The rank of the matrix ⎡⎢⎣−1252−4a−41−2a+1⎤⎥⎦ is if a=1 and if a=−6

A
2
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B
1
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C
3
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D
0.0
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Solution

The correct options are
A 2
B 1
A=12524a412a+1=00a+600a612a+1
[R1R1+R3 and R2R22R3]

=00000a612a+1
[R1R1+R2]

When a=6, A=000000125
ρ(A)=1, where ρ(A) is the number of non-zero rows which gives us the rank.

When a=6, A=0000012127
ρ(A)=2

When a=1, A=000007122
ρ(A)=2

When a=2, A=000008122
ρ(A)=2

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