The rank of the matrix A=⎡⎢⎣2314012−10−2−42⎤⎥⎦ is
A
2
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B
3
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C
1
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D
indeterminate
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Solution
The correct option is A 2 Given A=⎡⎢⎣2314012−10−2−42⎤⎥⎦ Rank of A ≤min3,4 So, rank of A≤3 Now, we will reduce it to Echelon form R3→R3+2R2 ⎡⎢⎣2314012−10000⎤⎥⎦ Here, row R3 has all elements 0. So, two non-zero rows. Hence, rank =2